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Proof step 5 from proof ks-RED (previous step)

∀ n0. n0 < 1 → (true → 〈RED(ks(n0); t)〉 ((even(n0) → t = K) ∧ (odd(n0) → t = K _ K))), t1 = K, value(ks(1) .2), value(t2), ap(ks(1) .1), ap(ks(1)), ks(1) .1 = t1 _ t2 ⊦ 〈RED(t2; t0)〉 t0 = K _ K

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ n0. n0 < 1 → (true → 〈RED(ks(n0); t)〉 ((even(n0) → t = K) ∧ (odd(n0) → t = K _ K))), ks(1) .1 = K _ t2, ap(ks(1)), value(t2), value(ks(1) .2) ⊦ 〈RED(t2; t0)〉 t0 = K _ K

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ap(t _ t0)])]]