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Proof step 91 from proof ks-RED (previous step)

∀ n0. n0 < n → (true → 〈RED(ks(n0); t)〉 ((even(n0) → t = K) ∧ (odd(n0) → t = K _ K))), n = 0 ∨ n = 1 ⊦ 〈RED(ks(n); t)〉 ((even(n) → t = K) ∧ (odd(n) → t = K _ K))

User applied rule call right

And obtained the following new goals

Proof step 1:
⊦
Proof step 90:
∀ n0. n0 < n → (true → 〈RED(ks(n0); t)〉 ((even(n0) → t = K) ∧ (odd(n0) → t = K _ K))), n = 0 ∨ n = 1 ⊦ 〈let tn = none in { RED1(ks(n); tn) ; if tn ≠ none then RED(tn .t; t0) else t0 := ks(n) }〉 ((even(n) → t0 = K) ∧ (odd(n) → t0 = K _ K))

Rule argument

[fmapos-arg: pos: right 1]

Additional information

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