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Proof step 36 from proof ks-RED1 (previous step)

〈RED1(ks(1); tn)〉 tn = none, t0 = S, ap(ks(1) .1), ap(ks(1)), ¬ value(ks(1)), ¬ (value(t1) ∧ value(ks(1) .2)), ¬ (ks(1) .1 = K ∧ value(ks(1) .2)), ks(1) .1 = t0 _ t1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 35:
〈RED1(ks(1); tn)〉 tn = none, ks(1) .1 = S _ t1, ap(ks(1)), ¬ value(ks(1)), ¬ (value(t1) ∧ value(ks(1) .2)) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ t _ t0 ≠ K], [CSIMPSEQ : ⊦ ap(t _ t0)])]]