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Proof step 70 from proof ks-RED1 (previous step)

〈RED1(ks(1); tn)〉 tn = none, ¬ value(ks(1)), ¬ (ap(ks(1)) ∧ ap(ks(1) .1) ∧ ks(1) .1 .1 = S), ¬ (ap(ks(1)) ∧ ks(1) .1 = K ∧ value(ks(1) .2)) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 69:
⊦ n ≠ 0 → ks(n) = ks(n -1) _ K

Rule argument

[x0lemmaarg: spec-name: termfuns instance-name: lemma-name: ks-rec-01 antecedent: succedent: n ≠ 0 → ks(n) = ks(n -1) _ K substlist: [n] → [1] add preconditions?: F is rewrite lemma?: T current spec?: F rotate lemma?: F replace all?: T paths: ((0, 0, 2, 1, 0, 1, 0, 1, 0)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ks(0) = K], [CSIMPSEQ : ⊦ value(K _ t) ↔ value(t)], [CSIMPSEQ : ⊦ value(K)])], [EXTRATERMS : (1)]]