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Proof step 86 from proof ks-RED1 (conclusion)

⊦ 〈RED1(ks(n); tn)〉 ((tn = none → n ≤ 1) ∧ (tn ≠ none → ¬ n ≤ 1 ∧ tn = some(ks(n - 2))))

User applied rule structural induction

And obtained the following new goals

Proof step 11:
⊦ 〈RED1(ks(0); tn)〉 ((tn = none → 0 ≤ 1) ∧ (tn ≠ none → ¬ 0 ≤ 1 ∧ tn = some(ks(0 - 2))))
Proof step 85:
〈RED1(ks(n0); tn)〉 ((tn = none → n0 ≤ 1) ∧ (tn ≠ none → ¬ n0 ≤ 1 ∧ tn = some(ks(n0 - 2)))) ⊦ 〈RED1(ks(n0 +1); tn)〉 ((tn = none → n0 +1 ≤ 1) ∧ (tn ≠ none → ¬ n0 +1 ≤ 1 ∧ tn = some(ks(n0 +1 - 2))))

Rule argument

[VARWITHVARSEQSARG : n, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : nat generated by 0, +1;])]]