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Proof step 14 from proof ks-TOPRED (previous step)

ap(ks(n)) ∧ ap(ks(n) .1) ∧ ks(n) .1 .1 = K ∧ value(ks(n) .1 .2) ∧ value(ks(n) .2) ⊦ 〈tn0 := some(ks(n) .1 .2)〉 (tn0 ≠ none → n = 2 ∧ tn0 = some(K))

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 13:
ap(ks(n)) ∧ ap(ks(n) .1) ∧ ks(n) .1 .1 = K ∧ value(ks(n) .1 .2) ∧ value(ks(n) .2), ¬ (some(ks(n) .1 .2) ≠ none → n = 2 ∧ some(ks(n) .1 .2) = some(K)) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]