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Proof step 21 from proof ks-TOPRED (previous step)

¬ (ap(ks(n)) ∧ ap(ks(n) .1) ∧ ks(n) .1 .1 = K ∧ value(ks(n) .1 .2) ∧ value(ks(n) .2)), ap(ks(n)) ∧ ap(ks(n) .1) ∧ ap(ks(n) .1 .1) ∧ ks(n) .1 .1 .1 = S, v = ks(n) .2, v0 = ks(n) .1 .2, v4 = ks(n) .1 .1 .2, value(v4) ∧ value(v0) ∧ value(v) ⊦ 〈tn0 := some(v4 _ v _ (v0 _ v))〉 (tn0 ≠ none → n = 2 ∧ tn0 = some(K))

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 20:
¬ (ap(ks(n)) ∧ ap(ks(n) .1) ∧ ks(n) .1 .1 = K ∧ value(ks(n) .1 .2) ∧ value(ks(n) .2)), ap(ks(n)) ∧ ap(ks(n) .1) ∧ ap(ks(n) .1 .1) ∧ ks(n) .1 .1 .1 = S, v = ks(n) .2, v0 = ks(n) .1 .2, v4 = ks(n) .1 .1 .2, value(v4) ∧ value(v0) ∧ value(v), ¬ (some(v4 _ v _ (v0 _ v)) ≠ none → n = 2 ∧ some(v4 _ v _ (v0 _ v)) = some(K)) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]