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Proof step 24 from proof ks-TOPRED (previous step)

¬ (ap(ks(n)) ∧ ap(ks(n) .1) ∧ ks(n) .1 .1 = K ∧ value(ks(n) .1 .2) ∧ value(ks(n) .2)), ap(ks(n)) ∧ ap(ks(n) .1) ∧ ap(ks(n) .1 .1) ∧ ks(n) .1 .1 .1 = S ⊦ 〈let v1 = ks(n) .1 .1 .2, v2 = ks(n) .1 .2, v3 = ks(n) .2 in if value(v1) ∧ value(v2) ∧ value(v3) then tn0 := some(v1 _ v3 _ (v2 _ v3)) else tn0 := none〉 (tn0 ≠ none → n = 2 ∧ tn0 = some(K))

Heuristic symbolic execution applied rule vardecls right

And obtained the following new goals

Proof step 23:
¬ (ap(ks(n)) ∧ ap(ks(n) .1) ∧ ks(n) .1 .1 = K ∧ value(ks(n) .1 .2) ∧ value(ks(n) .2)), ap(ks(n)) ∧ ap(ks(n) .1) ∧ ap(ks(n) .1 .1) ∧ ks(n) .1 .1 .1 = S, v = ks(n) .2, v0 = ks(n) .1 .2, v4 = ks(n) .1 .1 .2 ⊦ 〈if value(v4) ∧ value(v0) ∧ value(v) then tn0 := some(v4 _ v _ (v0 _ v)) else tn0 := none〉 (tn0 ≠ none → n = 2 ∧ tn0 = some(K))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]