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Proof step 8 from proof termination-RED (previous step)

〈RED1(t; tn)〉 tn = tn1, ∀ t0. #(t0) < #(t) → (¬ hasS(t0) → 〈RED(t0; t')〉 true), ¬ hasS(t), tn1 ≠ none → ¬ hasS(tn1) ∧ #(tn1) < #(t), ¬ tn1 ≠ none ⊦ 〈t0 := t〉 true

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]