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Proof step 124 from proof termination-RED1 (previous step)

∀ t0. #(t0) < #(t) → (¬ hasS(t0) → 〈RED1(t0; tn)〉 (tn ≠ none → ¬ hasS(tn) ∧ #(tn) < #(t0))), ¬ hasS(t), ¬ (ap(t) ∧ ap(t .1) ∧ t .1 .1 = K ∧ value(t .1 .2) ∧ value(t .2)), ¬ (ap(t) ∧ ap(t .1) ∧ ap(t .1 .1) ∧ t .1 .1 .1 = S), tn = none, ¬ (tn = none ∧ ap(t)) ⊦ 〈skip〉 (tn ≠ none → ¬ hasS(tn) ∧ #(tn) < #(t))

Heuristic symbolic execution applied rule skip right

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]