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Proof step 14 from proof termination-TOPRED (previous step)

¬ hasS(t), ¬ (ap(t) ∧ ap(t .1) ∧ t .1 .1 = K ∧ value(t .1 .2) ∧ value(t .2)), ap(t) ∧ ap(t .1) ∧ ap(t .1 .1) ∧ t .1 .1 .1 = S, v = t .2, v0 = t .1 .2, v4 = t .1 .1 .2, ¬ (value(v4) ∧ value(v0) ∧ value(v)) ⊦ 〈tn0 := none〉 (tn0 ≠ none → ¬ hasS(tn0) ∧ #(tn0) < #(t))

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]