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Proof step 7 from proof termination-TOPRED (previous step)

t2 .1 = S, ap(t2), value(t2 .2), value(t3), value(t1) ⊦ t2 = K, hasS(t1), hasS(t2), hasS(t3), ¬ hasS(t2 .2 _ t1 _ (t3 _ t1)) ∧ ¬ #(t2) ≤ #(t1) + #(t2 .2) + 1

Heuristic elimination applied rule insert elim lemma

And closed the goal!

Rule argument

[x0lemmaarg: spec-name: term instance-name: lemma-name: elim antecedent: succedent: ap(t) → (t0 = t .1 ∧ t1 = t .2 ↔ t = t0 _ t1) substlist: [t, t0, t1] → [t2, t, t0] add preconditions?: F is rewrite lemma?: F current spec?: F rotate lemma?: T replace all?: T paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ t _ t0 ≠ K], [CSIMPSEQ : ⊦ ap(t _ t0)], [CSIMPSEQ : ⊦ hasS(t _ t0) ↔ hasS(t) ∨ hasS(t0)], [CSIMPSEQ : ⊦ hasS(S)], [CSIMPELIM : ⊦ ap(t) → ( t0 = t .1 ∧ t1 = t .2 ↔ t = t0 _ t1)])], [EXTRATERMS : (t2, t, t0)]]