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Proof step 22 from proof irred-top (previous step)

value(v5), value(v1), value(v2), value(v3), context(C0), ∀ t'. ¬ v5 => t' ⊦ C0[S _ v1 _ v2 _ v3] => C0[v1 _ v3 _ (v2 _ v3)]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
⊦ t => t' ↔ (∃ C. (∃ v1, v2. t = C[K _ v1 _ v2] ∧ t' = C[v1] ∧ value(v1) ∧ value(v2) ∧ context(C)) ∨ (∃ v1, v2, v3. t = C[S _ v1 _ v2 _ v3] ∧ t' = C[v1 _ v3 _ (v2 _ v3)] ∧ value(v1) ∧ value(v2) ∧ value(v3) ∧ context(C)))
Proof step 21:
value(v5), value(v1), value(v2), value(v3), context(C0), ∀ t'. ¬ v5 => t' ⊦ ∃ C. (∃ v, v0. C0[S _ v1 _ v2 _ v3] = C[K _ v _ v0] ∧ C0[v1 _ v3 _ (v2 _ v3)] = C[v] ∧ value(v) ∧ value(v0) ∧ context(C)) ∨ (∃ v, v0, v4. C0[S _ v1 _ v2 _ v3] = C[S _ v _ v0 _ v4] ∧ C0[v1 _ v3 _ (v2 _ v3)] = C[v _ v4 _ (v0 _ v4)] ∧ value(v) ∧ value(v0) ∧ value(v4) ∧ context(C))

Rule argument

[x0lemmaarg: spec-name: instance-name: lemma-name: one-step-red-def antecedent: succedent: t => t' ↔ (∃ C. (∃ v1, v2. t = C[K _ v1 _ v2] ∧ t' = C[v1] ∧ value(v1) ∧ value(v2) ∧ context(C)) ∨ (∃ v1, v2, v3. t = C[S _ v1 _ v2 _ v3] ∧ t' = C[v1 _ v3 _ (v2 _ v3)] ∧ value(v1) ∧ value(v2) ∧ value(v3) ∧ context(C))) substlist: [t', t] → [C0[v1 _ v3 _ (v2 _ v3)], C0[S _ v1 _ v2 _ v3]] add preconditions?: F is rewrite lemma?: T current spec?: T rotate lemma?: F replace all?: T paths: ((1, 0, 0)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (C0[v1 _ v3 _ (v2 _ v3)], C0[S _ v1 _ v2 _ v3])]]