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Proof step 3 from proof it-rec-01 (conclusion)

⊦ n ≠ 0 → ((R ^ n)(t, t') ↔ (∃ t1. R(t, t1) ∧ (R ^ n -1)(t1, t')))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ n = 0, (R ^ n)(t, t') ↔ (∃ t0. R(t, t0) ∧ (R ^ (n - 1))(t0, t'))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ n -1 = n - 1])]]