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Proof step 10 from proof topred-unique (previous step)

(∃ v1, v2. t = K _ v1 _ v2 ∧ t2 = v1 ∧ value(v1) ∧ value(v2)) ∨ (∃ v1, v2, v3. t = S _ v1 _ v2 _ v3 ∧ t2 = v1 _ v3 _ (v2 _ v3) ∧ value(v1) ∧ value(v2) ∧ value(v3)), t =>top t1 ⊦ t1 = t2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
t =>top t1, t = K _ v _ v0 ∧ t2 = v ∧ value(v) ∧ value(v0) ∨ t = S _ v1 _ v2 _ v3 ∧ t2 = v1 _ v3 _ (v2 _ v3) ∧ value(v1) ∧ value(v2) ∧ value(v3) ⊦ t1 = t2

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]