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Proof step 7 from proof topred-unique (previous step)

t = K _ v _ v0 ∧ t2 = v ∧ value(v) ∧ value(v0) ∨ t = S _ v1 _ v2 _ v3 ∧ t2 = v1 _ v3 _ (v2 _ v3) ∧ value(v1) ∧ value(v2) ∧ value(v3), t = K _ v4 _ v5 ∧ t1 = v4 ∧ value(v4) ∧ value(v5) ∨ t = S _ v6 _ v7 _ v8 ∧ t1 = v6 _ v8 _ (v7 _ v8) ∧ value(v6) ∧ value(v7) ∧ value(v8) ⊦ t1 = t2

User applied rule cut formula

And obtained the following new goals

Proof step 4:
t = K _ v4 _ v5, t = K _ v _ v0 ∧ t2 = v ∧ value(v) ∧ value(v0) ∨ t = S _ v1 _ v2 _ v3 ∧ t2 = v1 _ v3 _ (v2 _ v3) ∧ value(v1) ∧ value(v2) ∧ value(v3), t = K _ v4 _ v5 ∧ t1 = v4 ∧ value(v4) ∧ value(v5) ∨ t = S _ v6 _ v7 _ v8 ∧ t1 = v6 _ v8 _ (v7 _ v8) ∧ value(v6) ∧ value(v7) ∧ value(v8) ⊦ t1 = t2
Proof step 6:
t = K _ v _ v0 ∧ t2 = v ∧ value(v) ∧ value(v0) ∨ t = S _ v1 _ v2 _ v3 ∧ t2 = v1 _ v3 _ (v2 _ v3) ∧ value(v1) ∧ value(v2) ∧ value(v3), t = K _ v4 _ v5 ∧ t1 = v4 ∧ value(v4) ∧ value(v5) ∨ t = S _ v6 _ v7 _ v8 ∧ t1 = v6 _ v8 _ (v7 _ v8) ∧ value(v6) ∧ value(v7) ∧ value(v8) ⊦ t = K _ v4 _ v5, t1 = t2

Rule argument

[fma-arg: t = K _ v4 _ v5]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (t = K _ v4 _ v5)]]