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Proof step 17 from proof not-value-02 (previous step)

C0 = t3 _ C, C0[S _ t _ t0 _ t1] .1 = S, value(t2), value(C0[S _ t _ t0 _ t1] .2), ∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
⊦ (t1 _ C)[t] = t1 _ C[t]
Proof step 16:
value(C[S _ t _ t0 _ t1]), value(t2), ∀ t3, t4, t5. ¬ value(C[S _ t3 _ t4 _ t5]) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ value(S _ t) ↔ value(t)], [CSIMPSEQ : ⊦ (t _ t0) .2 = t0], [CSIMPSEQ : ⊦ (t _ t0) .1 = t])]]