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Proof step 19 from proof not-value-02 (previous step)

C0[S _ t _ t0 _ t1] ≠ K ∧ C0[S _ t _ t0 _ t1] ≠ S, ap(C0[S _ t _ t0 _ t1]) ∧ C0[S _ t _ t0 _ t1] .1 = S ∧ value(t2) ∧ value(C0[S _ t _ t0 _ t1] .2), ∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
⊦ C[t _ t0] ≠ S
Proof step 10:
⊦ C[t _ t0] ≠ K
Proof step 11:
⊦ ap(C[t _ t1])
Proof step 18:
C0[S _ t _ t0 _ t1] .1 = S, value(t2), value(C0[S _ t _ t0 _ t1] .2), ∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]