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Proof step 21 from proof not-value-02 (previous step)

∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]), value((C0 _ t2)[S _ t _ t0 _ t1]) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ (C _ t1)[t] = C[t] _ t1
Proof step 20:
value(C0[S _ t _ t0 _ t1] _ t2), ∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]