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Proof step 27 from proof not-value-02 (previous step)

value(t2 _ C0[S _ t _ t0 _ t1]), ∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]) ⊦ t2 ≠ S

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 26:
value(C0[S _ t _ t0 _ t1]), ∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ value(S _ t) ↔ value(t)])]]