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Proof step 29 from proof not-value-02 (previous step)

¬ (t2 ≠ K ∧ t2 ≠ S), value(t2 _ C0[S _ t _ t0 _ t1]), ∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
value(t2 _ C0[S _ t _ t0 _ t1]), ∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]) ⊦ t2 ≠ K ∧ t2 ≠ S

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]