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Proof step 33 from proof not-value-02 (previous step)

t2 ≠ K ∧ t2 ≠ S, ap(t2) ∧ t2 .1 = S ∧ value(C0[S _ t _ t0 _ t1]) ∧ value(t2 .2), ∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
t2 .1 = S, value(t2 .2), value(C0[S _ t _ t0 _ t1]), ap(t2), ∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]) ⊦ t2 = K, t2 = S

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]