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Proof step 35 from proof not-value-02 (previous step)

∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]), value((t2 _ C0)[S _ t _ t0 _ t1]) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
⊦ (t1 _ C)[t] = t1 _ C[t]
Proof step 34:
value(t2 _ C0[S _ t _ t0 _ t1]), ∀ t, t0, t1. ¬ value(C0[S _ t _ t0 _ t1]) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]