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Proof step 29 from proof not-value (previous step)

¬ (t1 ≠ K ∧ t1 ≠ S), value(t1 _ C0[K _ t _ t0]), ∀ t, t0. ¬ value(C0[K _ t _ t0]) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
value(t1 _ C0[K _ t _ t0]), ∀ t, t0. ¬ value(C0[K _ t _ t0]) ⊦ t1 ≠ K ∧ t1 ≠ S

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]