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Proof step 31 from proof not-value (previous step)

t1 = t2 _ t3, t2 = S, value(t3), value(C0[K _ t _ t0]), ap(t1), ∀ t, t0. ¬ value(C0[K _ t _ t0]) ⊦ t1 = K, t1 = S

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
value(t3), value(C0[K _ t _ t0]), ∀ t, t0. ¬ value(C0[K _ t _ t0]) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ap(t _ t0)], [CSIMPSEQ : ⊦ t _ t0 ≠ S], [CSIMPSEQ : ⊦ t _ t0 ≠ K])]]