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Proof step 6 from proof ks-not-S (conclusion)

⊦ ks(n) ≠ S _ t1 _ t2 _ t3

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
ks(n) = S _ t1 _ t2 _ t3 ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]