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Proof step 3 from proof value-04 (conclusion)

⊦ ¬ value(S _ K _ K _ (K _ (S _ (S _ K _ K) _ (S _ K _ K)) _ (K _ (S _ (S _ K _ K) _ (S _ K _ K)))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
value(S _ K _ K _ (K _ (S _ (S _ K _ K) _ (S _ K _ K)) _ (K _ (S _ (S _ K _ K) _ (S _ K _ K))))) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]