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Proof step 5 from proof path-uni-com (previous step)

ispath(p, n0, n1, dirs1, files), dirs0 ⊥ dirs1, dirs1 ⊥ dirs0 ⊦ ispath(p, n0, n1, dirs1 ∪ dirs0, files)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
ispath(p, n0, n1, dirs1, files), dirs0 ⊥ dirs1 ⊦ ispath(p, n0, n1, dirs1 ∪ dirs0, files)

Rule argument

Additional information

Used simplifier rules: ⊦ dirs ⊥ dirs0 → dirs0 ⊥ dirs; (s)