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Proof step 6 from proof path-uni-com (previous step)

ispath(p, n0, n1, dirs1, files), dirs0 ⊥ dirs1 ⊦ ispath(p, n0, n1, dirs1 ∪ dirs0, files)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: path-uni seq: ⊦ dirs0 ⊥ dirs1 ∧ ispath(p, n0, n1, dirs0, files) → ispath(p, n0, n1, dirs0 ∪ dirs1, files) subst: [files, dirs1, dirs0, n1, n0, p] → [files, dirs0, dirs1, n1, n0, p] flags: <all paths>

Additional information

Used simplifier rules: ⊦ dirs ⊥ dirs0 → dirs0 ⊥ dirs; (s) Used terms: files, dirs0, dirs1, n1, n0, p