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Proof step 10 from proof abs-orphans (previous step)

afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)) ⊦ (inodekey(ino) ∈ ri ∧ fs[ri[inodekey(ino)]].directory ∨ inodekey(ino) ∈ ri ∧ ¬ fs[ri[inodekey(ino)]].directory) ∧ links(ino, abs-dirs(fs, ri)) = ∅ ↔ inodekey(ino) ∈ ri ∧ fs[ri[inodekey(ino)]].nlink = 0, ino = ROOT_INO

Heuristic nonsplitting cut applied rule cut formula

And obtained the following new goals

Proof step 11:
afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)), inodekey(ino) ∈ ri ⊦ (inodekey(ino) ∈ ri ∧ fs[ri[inodekey(ino)]].directory ∨ inodekey(ino) ∈ ri ∧ ¬ fs[ri[inodekey(ino)]].directory) ∧ links(ino, abs-dirs(fs, ri)) = ∅ ↔ inodekey(ino) ∈ ri ∧ fs[ri[inodekey(ino)]].nlink = 0, ino = ROOT_INO

Rule argument

fma: inodekey(ino) ∈ ri

Additional information

Used formulas: inodekey(ino) ∈ ri