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Proof step 9 from proof abs-orphans (previous step)

afs-cons(abs-dirs(fs, ri), abs-files(fs, ri)) ⊦ valid-ino(ino, abs-dirs(fs, ri), abs-files(fs, ri)) ∧ links(ino, abs-dirs(fs, ri)) = ∅ ∧ ino ≠ ROOT_INO ↔ inodekey(ino) ∈ ri ∧ fs[ri[inodekey(ino)]].nlink = 0, ino = ROOT_INO

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: in-dirs: ⊦ ino ∈ abs-dirs(fs, ri) ↔ inodekey(ino) ∈ ri ∧ fs[ri[inodekey(ino)]].directory;%in-files: ⊦ ino ∈ abs-files(fs, ri) ↔ inodekey(ino) ∈ ri ∧ ¬ fs[ri[inodekey(ino)]].directory;% ⊦ valid-ino(ino, dirs, files) ↔ ino ∈ dirs ∨ ino ∈ files; (s)