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Proof step 2 from proof div2-mult4-add-k (previous step)

⊦ (n0 + 4 * n) / 2 = n0 / 2 + 2 * n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ m0 % n = 0 ∧ 0 ≠ n → (m + m0) / n = m / n + m0 / n
Proof step 4:
⊦ (n0 + 4 * n) / 2 = n0 / 2 + 2 * n, (4 * n) % 2 = 0 ∧ 0 ≠ 2
Proof step 9:
(4 * n) % 2 = 0 ⊦ n0 / 2 + (4 * n) / 2 = n0 / 2 + 2 * n, 0 = 2

Rule argument

spec: nat-div name: div-add seq: ⊦ m0 % n = 0 ∧ 0 ≠ n → (m + m0) / n = m / n + m0 / n subst: [n, m0, m] → [2, 4 * n, n0] flags: <all paths>

Additional information

Used terms: 2, 4 * n, n0