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Proof step 9 from proof div2-mult4-add-k (previous step)

(4 * n) % 2 = 0 ⊦ n0 / 2 + (4 * n) / 2 = n0 / 2 + 2 * n, 0 = 2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
(4 * n) % 2 = 0 ⊦ (4 * n) / 2 = 2 * n

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + n = m + n0 ↔ n = n0; (s)