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Proof step 3 from proof keyset-eq-empty (previous step)

2exp-size(# bh.ar), heap-order(bh.ar, bh.size), no-dups-idx(bh.ar, bh.size), valid-idx(bh.ar, ar, bh.size), bh.size ≤ # bh.ar ⊦ keyset(bh.ar, bh.size) = ∅ ↔ bh.size = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
bh = bin-heap(kar, m), 2exp-size(# kar), heap-order(kar, m), no-dups-idx(kar, m), valid-idx(kar, ar, m), m ≤ # kar ⊦ keyset(kar, m) = ∅ ↔ m = 0

Rule argument

spec: bin-min-heap name: elim seq: ⊦ kar = bh.ar ∧ m = bh.size ↔ bh = bin-heap(kar, m) subst: [bh, kar, m] → [bh, kar, m]

Additional information

Used simplifier rules: ⊦ kar = bh.ar ∧ m = bh.size ↔ bh = bin-heap(kar, m); (elim) Used terms: bh, kar, m