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Proof step 4 from proof keyset-eq-empty (previous step)

bh = bin-heap(kar, m), 2exp-size(# kar), heap-order(kar, m), no-dups-idx(kar, m), valid-idx(kar, ar, m), m ≤ # kar ⊦ keyset(kar, m) = ∅ ↔ m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
keyset(kar, m) = ∅, 2exp-size(# kar), heap-order(kar, m), no-dups-idx(kar, m), valid-idx(kar, ar, m), m ≤ # kar ⊦ m = 0

Rule argument

Additional information

Used simplifier rules: ⊦ keyset(kar, 0) = ∅; (s)