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Proof step 18 from proof btree-inv-alloc (previous step)

((btree(null, null, adr, height0, false, fi, nodes(istore0), alladrs0, alladrs0, ok) * true))(zh0), ((btree(null, rp, adr, height, dirty, ri, nodes(istore), as, alladrs, ok) * true))(zh0), inv(istore), refsize-cons(istore0, alladrs0), refsize-cons(istore, as), adr ∈ istore, as ⊆ alladrs, as ⊆ dom nodes(istore), alladrs0 ⊆ dom nodes(istore), alladrs ⊆ dom nodes(istore), alladrs0 ⊆ dom nodes(istore0) ⊦ n ∈ istore, ∃ height, as, alladrs. ((btree(null, null, adr, height, false, fi, nodes(istore0), as, alladrs, ok) * true))(zh0) ∧ refsize-cons(istore0, as) ∧ alladrs ⊆ dom nodes(istore[n, indexblock(indx, lax, 0)])

User applied rule exists right

And obtained the following new goals

Proof step 19:
((btree(null, rp, adr, height, dirty, ri, nodes(istore), as, alladrs, ok) * true))(zh0), ((btree(null, null, adr, height0, false, fi, nodes(istore0), alladrs0, alladrs0, ok) * true))(zh0), inv(istore), refsize-cons(istore, as), refsize-cons(istore0, alladrs0), adr ∈ istore, alladrs0 ⊆ dom nodes(istore0), alladrs ⊆ dom nodes(istore), alladrs0 ⊆ dom nodes(istore), as ⊆ dom nodes(istore), as ⊆ alladrs ⊦ n ∈ istore, ((btree(null, null, adr, height0, false, fi, nodes(istore0), alladrs0, alladrs0, ok) * true))(zh0) ∧ refsize-cons(istore0, alladrs0) ∧ alladrs0 ⊆ dom nodes(istore[n, indexblock(indx, lax, 0)])

Rule argument

pos: right 2 terms: height0, alladrs0, alladrs0 abort: F discard: T computed: T

Additional information

Used terms: height0, alladrs0, alladrs0