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Proof step 19 from proof btree-inv-alloc (previous step)

((btree(null, rp, adr, height, dirty, ri, nodes(istore), as, alladrs, ok) * true))(zh0), ((btree(null, null, adr, height0, false, fi, nodes(istore0), alladrs0, alladrs0, ok) * true))(zh0), inv(istore), refsize-cons(istore, as), refsize-cons(istore0, alladrs0), adr ∈ istore, alladrs0 ⊆ dom nodes(istore0), alladrs ⊆ dom nodes(istore), alladrs0 ⊆ dom nodes(istore), as ⊆ dom nodes(istore), as ⊆ alladrs ⊦ n ∈ istore, ((btree(null, null, adr, height0, false, fi, nodes(istore0), alladrs0, alladrs0, ok) * true))(zh0) ∧ refsize-cons(istore0, alladrs0) ∧ alladrs0 ⊆ dom nodes(istore[n, indexblock(indx, lax, 0)])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
((btree(null, null, adr, height0, false, fi, nodes(istore0), alladrs0, alladrs0, ok) * true))(zh0), ((btree(null, rp, adr, height, dirty, ri, nodes(istore), as, alladrs, ok) * true))(zh0), inv(istore), refsize-cons(istore0, alladrs0), refsize-cons(istore, as), adr ∈ istore, as ⊆ alladrs, as ⊆ dom nodes(istore), alladrs0 ⊆ dom nodes(istore), alladrs ⊆ dom nodes(istore), alladrs0 ⊆ dom nodes(istore0) ⊦ n ∈ istore, alladrs0 ⊆ dom nodes(istore[n, indexblock(indx, lax, 0)]), dom nodes(istore0) ⊆ dom nodes(istore[n, indexblock(indx, lax, 0)]), dom nodes(istore) ⊆ dom nodes(istore[n, indexblock(indx, lax, 0)])

Rule argument

Additional information

Used simplifier rules: btree-crash: ⊦ (( btree (null, null, adr, height, false, fi, iast0, as, alladrs, ok) * true) )(zh0) → (( btree (null, null, adr, height, false, fi, iast0, as, alladrs, ok) * true) )(zh1);%sub-ntrans: ⊦ as ⊆ as0 ∧ ¬ as ⊆ as1 → ¬ as0 ⊆ as1; (forward) from specification set-basic[node-store]%sep-com: ⊦ P * P2 = P2 * P; from specification heap-sep[zheap]%sep-ass: ⊦ (P * P3) * P4 = P * P3 * P4; from specification heap-sep[zheap]