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Proof step 4 from proof btree-remove-context (previous step)

((btree(rp, r, adr, height, dirty, ri, iast, as, alladrs, ok) * P))(zh), as ⊆ alladrs, as ⊆ dom iast ⊦ P ≡ P ∧ ((btree(rp, r, adr, height, dirty, ri, iast, as, alladrs, ok) * P))(zh)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
((btree(rp, r, adr, height, dirty, ri, iast, as, alladrs, ok) * P))(zh), as ⊆ dom iast, as ⊆ alladrs ⊦ P ≡ P

Proof step 4 from proof btree-remove-context (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information