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Proof step 5 from proof btree-remove-context (
previous step
)
((btree(rp, r, adr, height, dirty, ri, iast, as, alladrs, ok) * P))(zh), as ⊆ dom iast, as ⊆ alladrs ⊦ P ≡ P
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 6
:
⊦ P0 ≡ P1 ↔ P0 = P1
Rule argument
spec: <toplevel> name: congruent seq: ⊦ P0 ≡ P1 ↔ P0 = P1 subst: [P1, P0] → [P, P] flags: <all paths>
Additional information
Used terms: P, P