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Proof step 14 from proof sorted-all (previous step)

n < # zbrar, n + m3 + 1 < # zbrar, sorted(zbrar, n + 1, m3 + 1), ∀ m, m0. m < m0 ∧ ¬ m3 + 1 < m0 → zbrar[n + m].key < zbrar[n + m0].key ⊦ sorted(zbrar, n + 1, m3 + 1) ∧ zbrar[n].key < zbrar[n + 1].key

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
n + m3 + 1 < # zbrar, n < # zbrar, sorted(zbrar, n + 1, m3 + 1), ∀ m, m0. m < m0 ∧ ¬ m3 + 1 < m0 → zbrar[n + m].key < zbrar[n + m0].key ⊦ zbrar[n].key < zbrar[n + 1].key

Proof step 14 from proof sorted-all (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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