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Proof step 15 from proof sorted-all (previous step)

n + m3 + 1 < # zbrar, n < # zbrar, sorted(zbrar, n + 1, m3 + 1), ∀ m, m0. m < m0 ∧ ¬ m3 + 1 < m0 → zbrar[n + m].key < zbrar[n + m0].key ⊦ zbrar[n].key < zbrar[n + 1].key

User applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: 0, 1 abort: F discard: F computed: F

Additional information

Used simplifier rules: ⊦ ¬ m < n → ¬ m + m0 < n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ n + 0 = n; (s) Used terms: 0, 1