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Proof step 1 from proof is-aligned-minus (conclusion)

m ≠ 0 ⊦ n1 ≤ n0 ∧ is-aligned(n0, m) ∧ is-aligned(n1, m) → is-aligned(n0 - n1, m)

System applied rule normalize

And obtained the following new goals

Proof step 2:
is-aligned(n0, m), is-aligned(n1, m), n1 ≤ n0 ⊦ m = 0, is-aligned(n0 - n1, m)

Rule argument

Additional information