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Proof step 2 from proof is-aligned-minus (previous step)

is-aligned(n0, m), is-aligned(n1, m), n1 ≤ n0 ⊦ m = 0, is-aligned(n0 - n1, m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ is-aligned(n, m) ↔ n % m = 0
Proof step 4:
n1 % m = 0, n0 % m = 0, n1 ≤ n0 ⊦ (n0 - n1) % m = 0, m = 0

Rule argument

Additional information

Used simplifier rules: is-aligned-def: ⊦ is-aligned(n, m) ↔ n % m = 0;