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Proof step 17 from proof append-a (previous step)

n < (# ar + # ar0) + # ar1, n < #(ar + ar0) ⊦ (ar + ar0)[n] = (ar + ar0 + ar1)[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: append-len: ⊦ #(ar0 + ar1) = # ar0 + # ar1;% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic