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Proof step 19 from proof append-a (previous step)

n < # ar + # ar0, n < (# ar + # ar0) + # ar1 ⊦ (ar + ar0)[n] = (ar + ar0 + ar1)[n]

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: append-at1 seq: ⊦ n < # ar0 → (ar0 + ar1)[n] = ar0[n] subst: [n, ar1, ar0] → [n, ar0, ar] flags: <all paths>

Additional information

Used simplifier rules: append-at1: ⊦ n < # ar0 → (ar0 + ar1)[n] = ar0[n]; Used terms: n, ar0, ar