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Proof step 12 from proof copy-shift-right (previous step)

n < # ar0 + # ar1, n < #(ar0 + ar1) ⊦ (n < n0 + # ar0 ∨ (n0 + # ar0) + m1 ≤ n ⊃ (ar0 + ar1)[n];ar[n + m - n0 + # ar0]) = (ar0 + copy(ar, m, ar1, n0, m1))[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: append-len: ⊦ #(ar0 + ar1) = # ar0 + # ar1;%append-a: ⊦ (ar + ar0) + ar1 = ar + ar0 + ar1;