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Proof step 8 from proof copy-shift-right (previous step)

n < # ar0 + # ar1 ⊦ copy(ar, m, ar0 + ar1, n0 + # ar0, m1)[n] = (ar0 + copy(ar, m, ar1, n0, m1))[n]

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: array-copy name: at-copy seq: ⊦ m0 < # ar1 → copy(ar0, n, ar1, n0, m)[m0] = (m0 < n0 ∨ n0 + m ≤ m0 ⊃ ar1[m0];ar0[m0 + n - n0]) subst: [m0, m, n0, ar1, n, ar0] → [n, m1, n0 + # ar0, ar0 + ar1, m, ar] flags: <all paths>

Additional information

Used simplifier rules: append-len: ⊦ #(ar0 + ar1) = # ar0 + # ar1;%append-a: ⊦ (ar + ar0) + ar1 = ar + ar0 + ar1;% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < n → (n ≤ m ↔ false); (s) Used terms: n, m1, n0 + # ar0, ar0 + ar1, m, ar