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Proof step 10 from proof range-eq-ext (previous step)

n < m0, n1 + m0 < # ar1, n0 + m0 < # ar0, ∀ n. ¬ m0 < n → ar0[n0 + n] = ar1[n1 + n] ⊦ ar0[(n0 + 1) + n] = ar1[(n1 + 1) + n], range=(ar0, n0 + 1, ar1, n1 + 1, m0)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: 1 + n

Additional information

Used simplifier rules: ⊦ m < n + 1 ↔ ¬ n < m; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used terms: 1 + n