[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Theorem range-eq-ext
⊦ range=(ar0, n0, ar1, n1, m) ↔ n0 + m ≤ # ar0 ∧ n1 + m ≤ # ar1 ∧ (∀ n. n < m → ar0[n0 + n] = ar1[n1 + n])
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
range-copy-drop
,
range-copy-inner
,
range-copy-lower
,
range-copy-outer
,
range-copy-upper
,
range-eq-append
,
range-eq-extract
,
range-eq-refl
,
range-eq-refl-simp
,
range-eq-resize
,
range-eq-shift-right
,
range-eq-splice-less
,
range-eq-subarrays
,
range-eq-sym
,
range-eq-trans
,
range-extend
,
rangeeq-write-left-above
,
rangeeq-write-left-below
,
Used by units in proved state:
datasize
,
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 6
Proof steps: 15
Used lemmas:
range-eq-rec
,
range-eq-0
,
Used spec theorems:
Used simplifier rules:
nat-basic
/
s-04
nat
/
lels
nat-basic
/
f
nat
/
succ-01
nat-basic
/
succ
nat-basic
/
zero-01
nat-basic
/
add-base
nat-basic
/
a
nat-basic
/
c