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Proof step 54 from proof range-eq-splice-less (previous step)

# ar0 < n0 + m1, n3 < m1, n3 < m0, n1 ≤ n0, m1 ≤ m0, n + m0 ≤ # ar, n2 + m1 ≤ # ar2, ∀ n3. n3 < m1 → ar2[n2 + n3] = copy(ar, n, resize(ar0, n0 + m1), n0, m1)[n1 + n3] ⊦ ar2[n2 + n3] = splice(ar, n, ar0, n0, m0)[n1 + n3]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 55:
⊦ # ar1 < n1 + m ∧ m ≠ 0 → splice(ar0, n0, ar1, n1, m) = copy(ar0, n0, resize(ar1, n1 + m), n1, m)
Proof step 56:
n3 < m0, n3 < m1, # ar0 < n0 + m1, # ar0 < n0 + m0, n2 + m1 ≤ # ar2, n + m0 ≤ # ar, m1 ≤ m0, n1 ≤ n0, ∀ n3. n3 < m1 → ar2[n2 + n3] = copy(ar, n, resize(ar0, n0 + m1), n0, m1)[n1 + n3] ⊦ ar2[n2 + n3] = copy(ar, n, resize(ar0, n0 + m0), n0, m0)[n1 + n3], m0 = 0

Rule argument

spec: <toplevel> name: splice-resize seq: ⊦ # ar1 < n1 + m ∧ m ≠ 0 → splice(ar0, n0, ar1, n1, m) = copy(ar0, n0, resize(ar1, n1 + m), n1, m) subst: [m, n1, ar1, n0, ar0] → [m0, n0, ar0, n, ar] flags: <all paths>

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)%fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat% ⊦ m + n < m + n0 ↔ n < n0; (s)% ⊦ m ≤ n → (n < m ↔ false); (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used terms: m0, n0, ar0, n, ar